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如何添加新字符串 datagridview 软件

如果添加字符串
DataTable



DataRow row = datatable1.NewRow//;

row["column2"]="column2";

row["column6"]="column6";

datatable1.Rows.Add/row/;


关于什么
DataGridView

??
2021-03-20 添加评论
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没有找到相关结果

    已邀请:

    裸奔

    赞同来自:

    你能做到吗：


    DataGridViewRow row = /DataGridViewRow/yourDataGridView.Rows[0].Clone//;
    
row.Cells[0].Value = "XYZ";
    
row.Cells[1].Value = 50.2;
    
yourDataGridView.Rows.Add/row/;


    或者：


    DataGridViewRow row = /DataGridViewRow/yourDataGridView.Rows[0].Clone//;
    
row.Cells["Column2"].Value = "XYZ";
    
row.Cells["Column6"].Value = 50.2;
    
yourDataGridView.Rows.Add/row/;


    其他方式：


    this.dataGridView1.Rows.Add/"five", "six", "seven","eight"/;
    
this.dataGridView1.Rows.Insert/0, "one", "two", "three", "four"/;


    经过：
    http://msdn.microsoft.com/en-u ... .aspx
    2021-03-21 0 0
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    三叔

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    类似于这个：


    var index = dgv.Rows.Add//;
    
dgv.Rows[index].Cells["Column1"].Value = "Column1";
    
dgv.Rows[index].Cells["Column2"].Value = 5.6;
    
//....
    2021-03-21 0 0
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    喜特乐

    赞同来自:

    假设你有 datagridview, 哪个未与数据集相关联，您希望以编程方式填充新行...

    这就是你的方式。


    // Create a new row first as it will include the columns you've created at design-time.
    

    
int rowId = dataGridView1.Rows.Add//;
    

    
// Grab the new row!
    
DataGridViewRow row = dataGridView1.Rows[rowId];
    

    
// Add the data
    
row.Cells["Column1"].Value = "Value1";
    
row.Cells["Column2"].Value = "Value2";
    

    
// And that's it! Quick and painless... :o/
    2021-03-21 0 0
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    八刀丁二

    赞同来自:

    类似于这个：


    dataGridView1.Columns[0].Name = "column2";
    
 dataGridView1.Columns[1].Name = "column6";
    

    
 string[] row1 = new string[] { "column2 value", "column6 value" };
    
 dataGridView1.Rows.Add/row1/;


    或者您需要安装是单独使用对象的值
    .Rows//

    , 像这样：


    dataGridView1.Rows[1].Cells[0].Value = "cell value";
    2021-03-21 0 0
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    三叔

    赞同来自:

    添加新行 DGV 没有线路

    Add//

    原因

    事件 SelectionChanged 在插入任何数据之前 /或标签属性中的对象绑定/.

    从中创建一个克隆字符串

    RowTemplate

    安全恕我直言：


    //assuming that you created columns /via code or designer/ in myDGV
    
DataGridViewRow row = /DataGridViewRow/ myDGV.RowTemplate.Clone//;
    
row.CreateCells/myDGV, "cell1", "cell2", "cell3"/;
    

    
myDGV.Rows.Add/row/;
    2021-03-21 0 0
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    帅驴

    赞同来自:

    这就是我添加字符串的方式 dgrview 空的 /myDataGridView 在我的例子中有两列/


    DataGridViewRow row = new DataGridViewRow//;
    
row.CreateCells/myDataGridView/;
    

    
row.Cells[0].Value = "some value";
    
row.Cells[1].Value = "next columns value";
    

    
myDataGridView.Rows.Add/row/;


    根据 docs: "CreateCells// 清除现有单元格并按照提供的模板设置其模板 DataGridView".
    2021-03-21 0 0
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    知食

    赞同来自:

    如果网格绑定到 DataSet / 表，那么它更好 BindingSource 作为


    var bindingSource = new BindingSource//;
    
bindingSource.DataSource = dataTable;
    
grid.DataSource = bindingSource;
    

    
//Add data to dataTable and then call
    

    
bindingSource.ResetBindings/false/
    2021-03-21 0 0
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    郭文康

    赞同来自:

    这是另一种做出的方法


    private void dataGridView1_CellContentClick/object sender, DataGridViewCellEventArgs e/
    
 {
    
 dataGridView1.ColumnCount = 3;
    

    
 dataGridView1.Columns[0].Name = "Name";
    
 dataGridView1.Columns[1].Name = "Age";
    
 dataGridView1.Columns[2].Name = "City";
    

    
 dataGridView1.Rows.Add/"kathir", "25", "salem"/;
    
 dataGridView1.Rows.Add/"vino", "24", "attur"/;
    
 dataGridView1.Rows.Add/"maruthi", "26", "dharmapuri"/;
    
 dataGridView1.Rows.Add/"arun", "27", "chennai"/; 
    
 }
    2021-03-21 0 0
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    郭文康

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    如果您需要操作任何操作，除了单元格值的行，例如添加标记，请尝试执行此操作：


    DataGridViewRow newRow = /DataGridViewRow/mappingDataGridView.RowTemplate.Clone//;
    
newRow.CreateCells/mappingDataGridView/;
    

    
newRow.Cells[0].Value = mapping.Key;
    
newRow.Cells[1].Value = //BusinessObject/mapping.Value/.Name;
    
newRow.Cells[1].Tag = mapping.Value;
    

    
mappingDataGridView.Rows.Add/newRow/;
    2021-03-21 0 0
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    快网

    赞同来自: 

    yourDGV.Rows.Add/column1,column2...columnx/; //add a row to a dataGridview
    
yourDGV.Rows[rowindex].Cells[Cell/Columnindex].value = yourvalue; //edit the value


    您还可以创建一个新字符串，然后添加它 DataGridView 通过以下方式：


    DataGridViewRow row = new DataGridViewRow//;
    
row.Cells[Cell/Columnindex].Value = yourvalue;
    
yourDGV.Rows.Add/row/;
    2021-03-21 0 0
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    知食

    赞同来自:

    如果你绑一个列表


    List<student> student = new List<student>//;
    

    
dataGridView1.DataSource = student.ToList//;
    
student .Add/new Student///;
    

    
//Reset the Datasource
    
dataGridView1.DataSource = null;
    
dataGridView1.DataSource = student;


    如果你被捆绑了 DataTable


    DataTable table = new DataTable//;
    

    
 DataRow newRow = table.NewRow//;
    

    
// Add the row to the rows collection.
    
table.Rows.Add/newRow/;


    </student></student>
    2021-03-21 0 0
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    詹大官人

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    复制字符串的示例 dataGridView 并在同一个中添加一个新字符串 dataGridView:


    DataTable Dt = new DataTable//;
    
Dt.Columns.Add/"Column1"/;
    
Dt.Columns.Add/"Column2"/;
    

    
DataRow dr = Dt.NewRow//;
    
DataGridViewRow dgvR = /DataGridViewRow/dataGridView1.CurrentRow;
    
dr[0] = dgvR.Cells[0].Value; 
    
dr[1] = dgvR.Cells[1].Value; 
    

    
Dt.Rows.Add/dR/;
    
dataGridView1.DataSource = Dt;
    2021-03-21 0 0
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    三叔

    赞同来自:

    考虑应用程序 Windows 和这个活动 Button Click 将此代码放入其中。


    dataGridView1.Rows
    
 .Add/new object[] { textBox1.Text, textBox2.Text, textBox3.Text }/;
    2021-03-21 0 0
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    莫问

    赞同来自: 

    //Add a list of BBDD
    
var item = myEntities.getList//.ToList//;
    
//Insert a new object of type in a position of the list 
    
item.Insert/0,/new Model.getList_Result { id = 0, name = "Coca Cola" }//;
    

    
//List assigned to DataGridView
    
dgList.DataSource = item;
    2021-03-21 0 0
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    快网

    赞同来自:

    如果您已经识别过 a
    DataSource

    , 你可以得到
    DataGridView

    s
    DataSource

    并带上它 A
    Datatable

    .

    然后添加新
    DataRow

    并设置字段的值。

    添加一个新字符串
    DataTable

    并接受变化。

    在 C# 一年是如此..


    DataTable dataTable = /DataTable/dataGridView.DataSource;
    
DataRow drToAdd = dataTable.NewRow//;
    

    
drToAdd["Field1"] = "Value1";
    
drToAdd["Field2"] = "Value2";
    

    
dataTable.Rows.Add/drToAdd/;
    
dataTable.AcceptChanges//;
    2021-03-21 0 0
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    卫东

    赞同来自: 

    //header
    
dataGridView1.RowCount = 50;
    
dataGridView1.Rows[0].HeaderCell.Value = "Product_ID0";
    

    

    
//add row by cell 
    
 dataGridView1.Rows[1].Cells[0].Value = "cell value";
    2021-03-21 0 0
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    郭文康

    赞同来自: 

    string[] splited = t.Split/'>'/;
    
int index = dgv_customers.Rows.Add/new DataGridViewRow///;
    
dgv_customers.Rows[index].Cells["cust_id"].Value=splited.WhichIsType/"id;"/;


    但要记住
    WhichIsType

    - 这是我创建的扩展方法。
    2021-03-21 0 0
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