Java: 作为 split 字符串的字符？

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我想他想要一个字符串 split 在尺寸的基板上 4. 然后我会在循环中做到：

List<string> strings = new ArrayList<string>//;

int index = 0;

while /index &lt; text.length/// {

 strings.add/text.substring/index, Math.min/index + 4,text.length/////;

 index += 4;

}

</string></string>

喜特乐

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使用
http://google.github.io/guava/ ... -int-
:

Iterable<string> result = Splitter.fixedLength/4/.split/"how are you?"/;

String[] parts = Iterables.toArray/result, String.class/;

</string>

莫问

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正常表达怎么样？

public static String[] splitByNumber/String str, int size/ {

 return /size<1 || str==null/ ? null : str.split/"/?<=\\G.{"+size+"}/"/;

}

看到字符串
https://coderoad.ru/3760152/

小姐请别说爱

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使用简单的基元 java 和周期。

private static String[] splitByNumber/String text, int number/ {



 int inLength = text.length//;

 int arLength = inLength / number;

 int left=inLength%number;

 if/left>0/{++arLength;}

 String ar[] = new String[arLength];

 String tempText=text;

 for /int x = 0; x < arLength; ++x/ {



 if/tempText.length//>number/{

 ar[x]=tempText.substring/0, number/;

 tempText=tempText.substring/number/;

 }else{

 ar[x]=tempText;

 }



 }





 return ar;

 }

使用：

String ar[]=splitByNumber/"nalaka", 2/;

二哥

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试试吧

String text = "how are you?";

 String array[] = text.split/" "/;

或者您可以在下面使用它

List<string> list= new ArrayList<string>//;

int index = 0;

while /index<text.length ;="" <="" code]="" div="" index="index+4;" index+4,text.length="" index,="" list.add="" math.min="" text.substring="" {="" }[="">

<div class="answer_text">

快速黑客





[code]private String[] splitByNumber/String s, int size/ {

 if/s == null || size &lt;= 0/

 return null;

 int chunks = s.length// / size + //s.length// % size &gt; 0/ ? 1 : 0/;

 String[] arr = new String[chunks];

 for/int i = 0, j = 0, l = s.length//; i &lt; l; i += size, j++/

 arr[j] = s.substring/i, Math.min/l, i + size//;

 return arr;

}

</div>
<div class="answer_text">
我不认为有一个解决方案 out-of-the-box, 但我会做这样的事情：

private String[] splitByNumber/String s, int chunkSize/{

 int chunkCount = /s.length// / chunkSize/ + /s.length// % chunkSize == 0 ? 0 : 1/;

 String[] returnVal = new String[chunkCount];

 for/int i=0;i<chunkcount;i++ *chunksize-1,="" 4="" ;="" ;[="" <="" [code]string[]="" code]="" div="" edit:="" i+1="" math.min="" return="" returnval;="" returnval[i]="s.substring/i*chunkSize," s.length="" textarray="splitByNumber/text," {="" }="" }[="" 使用将是：="" 实际上，子字段不应超过串的长度。="">

<div class="answer_text">

这是我可以提出的最简单的解决方案..尝试它





[code]public static String[] splitString/String str/ {

 if/str == null/ return null;



 List<string> list = new ArrayList<string>//;

 for/int i=0;i &lt; str.length//;i=i+4/{

 int endindex = Math.min/i+4,str.length///;

 list.add/str.substring/i, endindex//;

 }

 return list.toArray/new String[list.size//]/;

}

</string></string></div>
<div class="answer_text">
以下是使用流程的简要实现 Java8:

String text = "how are you?";

final AtomicInteger counter = new AtomicInteger/0/;

Collection<string> strings = text.chars//

 .mapToObj/i -&gt; String.valueOf//char/i/ /

 .collect/Collectors.groupingBy/it -&gt; counter.getAndIncrement// / 4

 ,Collectors.joining////

 .values//;

出口：

[how , are , you?]

</string></div>
<div class="answer_text">
尝试这个决定，

public static String[]chunkStringByLength/String inputString, int numOfChar/ {

 if /inputString == null || numOfChar &lt;= 0/

 return null;

 else if /inputString.length// == numOfChar/

 return new String[]{

 inputString

 };



 int chunkLen = /int/Math.ceil/inputString.length// / numOfChar/;

 String[]chunks = new String[chunkLen + 1];

 for /int i = 0; i &lt;= chunkLen; i++/ {

 int endLen = numOfChar;

 if /i == chunkLen/ {

 endLen = inputString.length// % numOfChar;

 }

 chunks[i] = new String/inputString.getBytes//, i * numOfChar, endLen/;

 }



 return chunks;

}

</div>
<div class="answer_text">
我的应用程序使用文本转换进行演讲！
这是我的算法 split 在 "dot" 如果字符串长度限制为限制，则组合字符串

String[] text = sentence.split/"\\."/;

 ArrayList<string> realText = sentenceSplitterWithCount/text/;

功能 sentenceSplitterWithCount: /我是一个连接线 lf 小于少 100 字符，这取决于你/

private ArrayList<string> sentenceSplitterWithCount/String[] splittedWithDot/{



 ArrayList<string> newArticleArray = new ArrayList&lt;&gt;//;

 String item = "";

 for/String sentence : splittedWithDot/{



 item += DataManager.setFirstCharCapitalize/sentence/+".";



 if/item.length// &gt; 100/{

 newArticleArray.add/item/;

 item = "";

 }



 }



 for /String a : newArticleArray/{

 Log.d/"tts", a/;



 }



 return newArticleArray;

 }

功能 setFirstCharCapitalize 只是标题第一个字母：我认为你仍然不需要它

public static String setFirstCharCapitalize/String input/ {





 if/input.length//&gt;2/ {

 String k = checkStringStartWithSpace/input/;

 input = k.substring/0, 1/.toUpperCase// + k.substring/1/.toLowerCase//;

 }



 return input;

 }

</string></string></string></div>
</chunkcount;i++></div></text.length></string></string>

喜特乐

赞同来自:

快速黑客

private String[] splitByNumber/String s, int size/ {

 if/s == null || size <= 0/

 return null;

 int chunks = s.length// / size + //s.length// % size > 0/ ? 1 : 0/;

 String[] arr = new String[chunks];

 for/int i = 0, j = 0, l = s.length//; i < l; i += size, j++/

 arr[j] = s.substring/i, Math.min/l, i + size//;

 return arr;

}

奔跑吧少年

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我不认为有一个解决方案 out-of-the-box, 但我会做这样的事情：

private String[] splitByNumber/String s, int chunkSize/{

 int chunkCount = /s.length// / chunkSize/ + /s.length// % chunkSize == 0 ? 0 : 1/;

 String[] returnVal = new String[chunkCount];

 for/int i=0;i<chunkcount;i++ *chunksize-1,="" 4="" ;="" ;[="" <="" [code]string[]="" code]="" div="" edit:="" i+1="" math.min="" return="" returnval;="" returnval[i]="s.substring/i*chunkSize," s.length="" textarray="splitByNumber/text," {="" }="" }[="" 使用将是：="" 实际上，子字段不应超过串的长度。="">

<div class="answer_text">

这是我可以提出的最简单的解决方案..尝试它





[code]public static String[] splitString/String str/ {

 if/str == null/ return null;



 List<string> list = new ArrayList<string>//;

 for/int i=0;i &lt; str.length//;i=i+4/{

 int endindex = Math.min/i+4,str.length///;

 list.add/str.substring/i, endindex//;

 }

 return list.toArray/new String[list.size//]/;

}

</string></string></div>
<div class="answer_text">
以下是使用流程的简要实现 Java8:

String text = "how are you?";

final AtomicInteger counter = new AtomicInteger/0/;

Collection<string> strings = text.chars//

 .mapToObj/i -&gt; String.valueOf//char/i/ /

 .collect/Collectors.groupingBy/it -&gt; counter.getAndIncrement// / 4

 ,Collectors.joining////

 .values//;

出口：

[how , are , you?]

</string></div>
<div class="answer_text">
尝试这个决定，

public static String[]chunkStringByLength/String inputString, int numOfChar/ {

 if /inputString == null || numOfChar &lt;= 0/

 return null;

 else if /inputString.length// == numOfChar/

 return new String[]{

 inputString

 };



 int chunkLen = /int/Math.ceil/inputString.length// / numOfChar/;

 String[]chunks = new String[chunkLen + 1];

 for /int i = 0; i &lt;= chunkLen; i++/ {

 int endLen = numOfChar;

 if /i == chunkLen/ {

 endLen = inputString.length// % numOfChar;

 }

 chunks[i] = new String/inputString.getBytes//, i * numOfChar, endLen/;

 }



 return chunks;

}

</div>
<div class="answer_text">
我的应用程序使用文本转换进行演讲！
这是我的算法 split 在 "dot" 如果字符串长度限制为限制，则组合字符串

String[] text = sentence.split/"\\."/;

 ArrayList<string> realText = sentenceSplitterWithCount/text/;

功能 sentenceSplitterWithCount: /我是一个连接线 lf 小于少 100 字符，这取决于你/

private ArrayList<string> sentenceSplitterWithCount/String[] splittedWithDot/{



 ArrayList<string> newArticleArray = new ArrayList&lt;&gt;//;

 String item = "";

 for/String sentence : splittedWithDot/{



 item += DataManager.setFirstCharCapitalize/sentence/+".";



 if/item.length// &gt; 100/{

 newArticleArray.add/item/;

 item = "";

 }



 }



 for /String a : newArticleArray/{

 Log.d/"tts", a/;



 }



 return newArticleArray;

 }

功能 setFirstCharCapitalize 只是标题第一个字母：我认为你仍然不需要它

public static String setFirstCharCapitalize/String input/ {





 if/input.length//&gt;2/ {

 String k = checkStringStartWithSpace/input/;

 input = k.substring/0, 1/.toUpperCase// + k.substring/1/.toLowerCase//;

 }



 return input;

 }

</string></string></string></div>
</chunkcount;i++>

八刀丁二

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这是我可以提出的最简单的解决方案..尝试它

public static String[] splitString/String str/ {

 if/str == null/ return null;



 List<string> list = new ArrayList<string>//;

 for/int i=0;i &lt; str.length//;i=i+4/{

 int endindex = Math.min/i+4,str.length///;

 list.add/str.substring/i, endindex//;

 }

 return list.toArray/new String[list.size//]/;

}

</string></string>

董宝中

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以下是使用流程的简要实现 Java8:

String text = "how are you?";

final AtomicInteger counter = new AtomicInteger/0/;

Collection<string> strings = text.chars//

 .mapToObj/i -&gt; String.valueOf//char/i/ /

 .collect/Collectors.groupingBy/it -&gt; counter.getAndIncrement// / 4

 ,Collectors.joining////

 .values//;

出口：

[how , are , you?]

</string>

诸葛浮云

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尝试这个决定，

public static String[]chunkStringByLength/String inputString, int numOfChar/ {

 if /inputString == null || numOfChar <= 0/

 return null;

 else if /inputString.length// == numOfChar/

 return new String[]{

 inputString

 };



 int chunkLen = /int/Math.ceil/inputString.length// / numOfChar/;

 String[]chunks = new String[chunkLen + 1];

 for /int i = 0; i <= chunkLen; i++/ {

 int endLen = numOfChar;

 if /i == chunkLen/ {

 endLen = inputString.length// % numOfChar;

 }

 chunks[i] = new String/inputString.getBytes//, i * numOfChar, endLen/;

 }



 return chunks;

}

冰洋

赞同来自:

我的应用程序使用文本转换进行演讲！
这是我的算法 split 在 "dot" 如果字符串长度限制为限制，则组合字符串

String[] text = sentence.split/"\\."/;

 ArrayList<string> realText = sentenceSplitterWithCount/text/;

功能 sentenceSplitterWithCount: /我是一个连接线 lf 小于少 100 字符，这取决于你/

private ArrayList<string> sentenceSplitterWithCount/String[] splittedWithDot/{



 ArrayList<string> newArticleArray = new ArrayList&lt;&gt;//;

 String item = "";

 for/String sentence : splittedWithDot/{



 item += DataManager.setFirstCharCapitalize/sentence/+".";



 if/item.length// &gt; 100/{

 newArticleArray.add/item/;

 item = "";

 }



 }



 for /String a : newArticleArray/{

 Log.d/"tts", a/;



 }



 return newArticleArray;

 }

功能 setFirstCharCapitalize 只是标题第一个字母：我认为你仍然不需要它

public static String setFirstCharCapitalize/String input/ {





 if/input.length//&gt;2/ {

 String k = checkStringStartWithSpace/input/;

 input = k.substring/0, 1/.toUpperCase// + k.substring/1/.toLowerCase//;

 }



 return input;

 }

</string></string></string>

Java: 作为 split 字符串的字符？

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